The circuit in itself will work as a cut off switch,
The original diagram was used probably because the device being powered was not 12V, but anything above 12V would essentially flip the switch.
Over current, a fuse, a slow blow, perhaps, depends on configuration.
You will also want to make a note of inrush current (the "instant" current taken at system switch on) as if for example a lot of caps etc are being charged, it can take a hefty slap of power from the battery, sometimes fuses will blow too quickly, so you have to make sure you get the right one (slow blow).
Most of the automotive gear will work past 12V due to 14+V from the alternator.
In your circuit essentially the zener (D2) is the trigger for the transistor.
EDIT: Actually thinking about it, if your alternator is charging you battery at say, 13.8V your circuit would probably cut off depending on component thresholds, you would be better using a 14V zener or something, or if your equipment is really that tight on tolerances (automotive generally isn't) then a regulator.