This may be to simple, but takes a bunch of resistors.
The signal you want to clone is between the sensor and the gauge. You just need to sense this with out effecting the gauge one.
If you send a small current out via a high resistance to the gauge/sensor connection and then back via a second high resistance path the gauge would not know this happened as long as the two currents matched. The catch is that the two paths need to be balanced above and below the gauge/sensor connection to get this matching.
http://en.wikipedia.org/wiki/Wheatstone_bridgeUse three bridges
two matching bridges as part of a third bridge.
In that drawing, the first two bridges will have matching values.
R1 = R2 lower resistance for current balance side
R3 = Rx High resistance for gauge sense connection
For bridge one, Connect point B of the bridge to the gauge where the sensor connects. Use two wires so that point B is actually at the gauge connection. R3 via wire to point B at gauge, second wire back connecting to Rx
The second bridge has no added connections. it is just used for matching the first.
Now take these two matching bridges and insert them in a third bridge.
For the third bridge all resistors match R1 = R3 = R2 = Rx
The first bridge is inserted between Rx & point B.
The second bridge is inserted between R3 & point D.
Assuming the proper resistors match, Point D of the first two bridges will only match when an equal current is flowing out and back from the gauge. To get this match to happen you change the voltage across bridge three.
The voltage across bridge three will also change with the signal at the gauge.
U1 in above is a differential input opamp.
The resistor values just show what resistors that need to match in value.
If the opamp does not keep the balance the meter reading will change some.
Someone might suggest using fewer resistors or getting the signal from a different spot. It is much easer to get all this to balance with matching resistors on each side. Like wise, any current drawn from the circuit must be done in a balanced manner to maintain a close current match out to the gauge-sensor connection.
Note: this circuit should be close to the gauge connection sensed.
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in the old days a gain & span circuit was used a lot.
For an oscope the span control is like the vertical position control while the gain control is Volts/div.
The problem with this circuit is that the two controls interact.
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It may be better/easer to just use a high power output opamp like the ST L165 which is cheap instead of messing with the added transistor.
As opamps like to operate in the center between it's supply and most do not like high cap loads use a resistor T network on the output. The two resistors in series helps protect the Opamp from non resistance loads while the third resistor adds some additional pull down to allow the Opamp to work closer to center.
Just an idea
Edit: Sorry left out the big part that is reason for working to get the balanced currents. A Very low value current sense resistor between the two connection points to the bridge network just above X2. This sense resistor would have the currents flowing through it from the gauge and the current from the bridge network. With the leads from the bridge connected one way these two currents would add, while a reversed connection from the bridge cancels some or all the added current sensor resistance. The top of B1R1 & bottom of B1R2 will be effected by this current change caused by the original sensor, this is the I. Point A is the E.
Good old E = I * R
The original meter controls and uses E & I while the Original sensor controls R.
To clone this sensor you need to know both E & I being used to be able to clone a new sensor fake to run the second meter.
C