thank you linux-works and maurish for your great help about inserting pics!
ok, this is a kindergarten level question. please excuse the ignorance, i need to get this clarified in order to understand how a Clamper Circuit works, from its physical side, as opposed to its mathematical side.
if we charge up a capacitor in a way it can get charged,
the two sides of it will acquire an equal amount of charges but of opposite types, positive and negative. yeah?
this situation,
will never happen provided there is current path to both sides, because that is not the way a capacitor behaves, correct?
now, if a circuit is setup this way,
one side of C1, netA, will have 5V, but this has nothing to do with capacitor charging, because the other side of C1, netC, is open, therefore there is no current path to it for current flow, and there won't be any charging happening. C1 is superfluous to the circuit, its charging/discharging function as a capacitor is not being used.
voltage of netC in this case is uncertain.
is this correct?
i'm reading a text book now, which gives a Clamper Circuit like this,
assuming the initial condition is such that the sinusoidal signal starts from 0V to Vpk, Vin=Vout=0V, forward biasing voltage and forward biasing resistance of D1 are both 0V as well, then D1 is not conducting, open circuit there, and C1 is in the same situation as the previous pic, i.e. it is not functioning as a capacitor and no charging/discharging can be talked about, because the Vout side of it has no current path for current to flow.
this text book also gives a set of curves,
which shows C1 is charged to a constant voltage of Vpk. it merely says "capacitor voltage", i'm not clear on whether that means Vin or Vout with both referencing ground, or referencing each other, or whatever.
in all cases, how can this be? the other side of C1, Vout, is an open circuit at all times, its voltage has nothing to do with how Vin varies, and because of this D1 will never be turned on.
nonetheless, LTSpice simulation shows this circuit is really working!
where did i go wrong in my above reasoning?
thank you all for helping!