If I understand correctly, the final load is 50 Ohms.
Consider that you have a RC filter, and that 60Hz is about 7.4 octaves below 10kHz. This means that, for a good HPF, the best you can expect is the noise being attenuated 6*7.4 = 44.4 dB with respect to the signal. Since the noise is about 20dB over the signal, the best final result is getting the noise about 24.4dB below the signal. If you look at the Fourier output of your circuit (C=10nF, R=47), you get about 24dB, which is almost optimal. You cannot expect much more from a simple RC filter than that.
The problem with your values is that the output signal is too attenuated by the filter: it's about 4.2mV peak to peak, if I'm not mistaken. You can improve that.
Playing a bit with series and parallel resistances, and voltage dividers, it's easy to compute the transfer function for the filter with 50 Ohms load.
\$\displaystyle \frac{s\, 50 R_f C}{R_f + R_o + s C\left[50 R_f + (50+R_f)R_0\right]}\$
Where Ro = 1050 the output impedance, Rf the filter resistance, C the filter capacitance. You can see there is a single zero at DC and a pole, typical highpass filter. The high-pass attenuation can be computed taking the limit with s to infinity and aproximating:
\$\displaystyle \frac{50 R_f}{(50+R_f)R_o}\$
If you make Rf = 47, you get an attenuation of 0.02. This is near to the minimum, which is at 25 Ohms. The best we can get is about 50/Ro = 0.047. If we take Rf = Ro = 1050, we achieve an attenuation of 0.045 (extremely close to optimal) and our formulas get simpler.
So it's a good idea to take the filter resistor equal to 1050 Ohms.
Now, to get optimal filtering, we should place the pole as close to 10kHz as possible. The pole is:
\$\displaystyle R_f + R_o + sC\left[50R_f + (50+R_f)R_o\right]\$
Solving, using Rf = Ro, the angular frequency is about \$2/R_o C\$. So, for a 10kHz frequency, C = 30nF. Probably you want to move the pole a bit, so perhaps a value of 15-25nF would give better attenuation.
My suggestion: R = 1050 ohms, C=15nF. The output is 36mV p2p and the noise is 23dB below signal.