Hello everybody,
I want to construct a DC-DC isolated zeta converter with the following specification
Input voltage:
-min 8V
-max 14V
Output voltage:
-constant 5V
Output power:
-min 5W
-max 12W
The ripple current throug the inductances(L2 and Lm) are set to 1/4*current throug them, the ripple through the first capacitor(C1) is chosen at 1/10*voltage through it, and the ripple through the output capacitor(C2) is set at 100mVpp.
Case 1:
-input voltage Vg=8V and output power P=5W
-in this case the load(R1) is 5ohm, the duty cycle is 0.55, and the n parameter for the transformer is n=0.5. The M parameter for the converter is M=Vo/V1=0.625.
-the output voltage is fixed around 4.2V, instead of 5V and I believe that the ripple from the output is too high.
The other cases are:
-V1=14V, P=5W
-V1=8V, P=12W
-V1=14V, P=12W
I don't understant why the output voltage is fixed around 4.2V, and why the ripple is so high. The components in the other cases are different from this one and they depend on the input voltage and on the output power. Maybe I don't know how to read the results of the simulation or they are wrong.
I've attached a few prinscreens with the schematic, output voltage and with the litteral expression of the currents through the inductances and with the voltages through capacitors.
Im=current through the magnetizing inductande
Il2=current through the second inductance
Vc1 and Vc1 are the voltages through the capacitors
PS: this is the ideal case of the convertor.Thank you,
GuilTy