Without any external load - and assuming that all capacitors are large enough for coupling the 1kHz - the actual gain is Av=-6k/25=-240.
Because I do not see that the load is specified, the remaining task is to find the proper load resistor for reducing the gain to -200.
That is a simple task.
In case, the load is given the effective gain determining resistor is 6k||10k=3.75 kohms and the gain can never reach the value of -200.
(Av=-3.75k/25=-150) .
Comment: Modifying the base resistors cannot help at all because it is the transconductance (gm=1/re) that matters only (as far as gain is concerned).