Hi!
This is my first topic and i'm not sure where i should post it, it's a fix, but it's also a newbie question so i figured this is the right place.
My printer recently suffered a common problem where the lever that detects the main cover position broke off and makes it impossible to print anything since it's stuck in the open position.
I have little knowledge about the operation of a photo-interrupter and i'm wondering if i can replace it easily soldering a few wires and a manual external on-off switch that i can use to send the "cover open" or "cover closed" signal to the processor so i can send the closed cover signal to print or the open cover signal to change the cartridges (They get locked if the processor thinks the cover is closed).
I read a few common photo-interrupters datasheets and my conclusion was that the output was 0V for low logic signal and 5V for high logic signal however i'm not sure if (and how) i can simulate that with a on-off switch.
Here´s a link to a imgurl album with a few pics of the photo-interrupter.
http://imgur.com/a/ageZEThanks in advance,
Rentium.