So is resistor divider just a point between two resistors to get a voltage drop or is there anything else to it ? I see one side of two resistors in series connected to Vcc and the other end to GND. A reading take from the center, so what is the point of having the second resistor connected to GND.
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With a single supply, say 12V, the two resistors in series will draw a certain amount of current. Let's say the resistors are 1k so the total is 2k and there will be 6 mA flowing. Now, that 6 mA flowing through the bottom resistor drops 6V and voila', we have divided our power supply voltage in half at the junction. We call the junction a virtual ground. Everything from now on will be referenced to that virtual ground.
Now we apply the virtual ground to the + input and we can accept incoming signals from about 2V to 13V (depending on the op amp). But note that the incoming signal on the - terminal has to be centered around the 6V on the + pin. Achieving that is a separate issue. If we really want to measure an AC signal, we will have to bias it up by 6V DC. Later on you will run into capacitive coupling. Basically, another voltage divider but with much higher resistor values (so as to not load the previous stage) and a capacitor.
It is so much easier to wrap your head around op amps with dual supplies. Then you can accept inputs between perhaps -10V and +10V and your AC signal doesn't need to be offset. BTW, there's a reason that Analog Computers using integrated circuit op amps use +- 15V supplies and generally have signal swings between +- 10V. That leaves plenty of headroom on both ends to keep the op amps from saturating or going non-linear.
I would try my very best to have dual supplies. In the early days it is so much easier to understand what is going on. Yes, I know, almost all op amp circuits today are using single supplies. Well, sure, they're designed by pros!