well.. about the whole deal involving measuring current using an o-scope, I dont know how to do it and prolly wont end up doing it..
about the cap, I figured that i can calculate the value by 1=c dv/dt, where dv= ripple voltage desired and dt = 8.333 ms for 60Hz fully rectified..so since my requirement for the output power is 20V @ 2A---> this means that a 10% ripple @ 20V is 2V.
I i can get away with 10,000uf!!---however... a 20,000uF will get me 5% ripple and 30,000uF will get me a 2.5% ripple..... at least in theory... however, the cap size isant really an issue.. the issue is the in rush current..
The reason why I began to worry about the in rush current is because I dont understand it and anything that I dont understand, I dont trust and can't be too sure about. I can believe the words of experienced individuals such as ur self.. but if I was calculate it for instance, I would be more assured that an in rush current wont be an issue..
I just dont want to fry anything...i.e over load the transformer, or have the massive 10,000uF blow in my face.. (i have been wearing safety goggles ever since I started to mess around with power stuff
)
BTW.. i wish an engineering degree had prepared me for this..it really didnt..