Author Topic: In series battery discharge test question: how do buck converters draw current?  (Read 2695 times)

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Offline BarkutiTopic starter

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Hello fellows! :popcorn:

Received a 6-pack package of Samsung ICR18650-30B cells from an AliExpress seller recently, and I need to do some sort of accurate testing over 'em. No analyzing charger yet, I have a Lii-500 on the slow boat from china though.
Thanks to HKJ's testing I know these cells should deliver ±9.5W of energy when discharged at 0.2A down to 2.8V. For reference graph:



The test is fairly old and done on his old station (no 4 terminal holder) but the slow discharge figures should be nicely accurate.
I do plan on setting a low voltage light load attached to an XL4015 buck module fed by all 6 cells in series connected by 8×1.5mm neodymium magnets and some copper sheet. My idea is to adjust the buck module for ±4.8W total power and measure the time it takes for its input voltage to drop below 16.8V starting from ±4.2V loaded cells. This means I need to adjust buck module load power to ±4.08W for 85% module efficiency.

But, well, as this is it may already be hard enough to attain any meaningful results. Problem is… how is the buck module going to draw power from the cells? Will it draw short bursts (low duty cycle, <20%) of 1+A current? Since I need to toss in the disspated power in the contacts this is of importance, I believe. The power factor, or sort of.

Thanks and cheers
« Last Edit: February 01, 2018, 10:17:38 pm by Barkuti »
 

Offline BarkutiTopic starter

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Oh well, the high switching frequency plus the decoupling caps, thanks for pointing this out blueskull.
Yes, main issue here is to determine if the cells are what they should. Wrapping and markings seem legit, cells' flat tops have 4 wide lobes instead of 3 but I know cells from the big 4 manufacturers are assembled in a variety of genuine plants.
With respect to total load power I aim to adjust it in a way that average current draw is close to 0.2A, aiming for ±12 hours of discharge time if all goes well. This is all homecooked, will have to watch out for the input voltage as I don't have a 6S BMS at hand.

Thanks and cheers
« Last Edit: February 01, 2018, 10:43:15 pm by Barkuti »
 

Offline T3sl4co1l

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FYI, if you're building this from scratch rather than using a battery manager -- battery impedance rises as voltage falls, so there comes a point when you can't maintain output power.  This is important for switching supplies, which increase input current as input voltage falls, to maintain a regulated output.

That's apparent from the discharge curves, though it may not be obvious or explicit.  Simply, the curves drop away that much faster, at higher currents, whether you've been drawing a high current or not.  It's a state-of-charge thing. :)

I built a flashlight from scratch, using discrete circuitry, and added a low-input-voltage throttle for this reason.  Indeed, in my case it was not only nice to the battery but a required function, as the control circuit is also powered from the single cell, and if the control browns out, the whole circuit is... not very happy! ;D

Tim
Seven Transistor Labs, LLC
Electronic design, from concept to prototype.
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Offline BarkutiTopic starter

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Battery impedance rises as voltage falls… yes I know T3sl4co1l. However, this mostly happens near the end of discharge point/voltage.
Speaking of state of charge, my testing setup is now at the 12 hour mark, input voltage is still above 18V. Adjusted output voltage to the (led) load is 3.23V, current 1.26A… 4.0698W / n = 4.677931034483W total load power for efficiency n = 0.87.
12h delivered energy: E = 4.677931034483W × 12h = 56.135172413796Wh, looks really good (goal is 57Wh). :popcorn:
My observed voltage profile has not matched the aforeposted curve(s), but the output energy does.

Cheers ;D
« Last Edit: February 02, 2018, 04:12:34 pm by Barkuti »
 

Offline BarkutiTopic starter

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6S input voltage fell below 16.7V (on my +0.5% :-DMM meter) briefly after hitting 12h 39m on the clock, at such point input current was close to 300mA.
Guesstimated delivered energy = 4.677931034483W × 12.65h = 59.17582758621Wh
As far as my wisdom goes, looks great and perfectly within error margin. :clap:

Cheers
 

Offline BarkutiTopic starter

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My observed voltage profile has not matched the aforeposted curve(s), but the output energy does.

Cheers ;D
And I know :palm: why. These cells are fake, found 'em destroyed after charging them up to 4.35V and letting them rest for an hour. :-\
Related: Seems like I got a six-pack of counterfeit/fake Samsung ICR18650-30B cells :-/

Cheers my dears
 


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