Author Topic: IR3315 current sense high side switch circuit explanation  (Read 2634 times)

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Offline johmTopic starter

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IR3315 current sense high side switch circuit explanation
« on: April 03, 2015, 09:40:09 pm »
Hello!

I'd like to use the IR3315 as overload protection, amongst others, but I don't fully understand how to drive the input control signal |O.



So:
- If Vin is referenced to Vcc, when Vcc-Vin reaches VIH the output is ON. (OK, then) Is it alright to connect Vin to Vcc? In case Vcc is shorted to GND will it stop properly and rearm again after this WAIT time has passed?

A bit of insight will be fully appreciated.

Datasheet: http://www.irf.com/product-info/datasheets/data/ir3315pbf.pdf
AppNote: http://www.irf.com/technical-info/appnotes/an-1118.pdf (page 10, section "Controlling IR331X by one wire")
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Offline mikeselectricstuff

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Re: IR3315 current sense high side switch circuit explanation
« Reply #1 on: April 03, 2015, 10:07:27 pm »
IN is the on/off control - pull it low (up to 37v below Vin) to turn on.
In the case of a fault trip, you need to turn off & on to restore output
The device has no ground connection - it derives its internal supply from the current coming out of the IN pin.
The diagram you show is wrong - look at the datasheet - th ediagram on the first page is fairly clear (though you usually don't need to look at the current feedback output, and it's drawn slightly unconventionally in that the supply is coming from the right) 
« Last Edit: April 03, 2015, 10:22:28 pm by mikeselectricstuff »
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Offline johmTopic starter

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Re: IR3315 current sense high side switch circuit explanation
« Reply #2 on: April 03, 2015, 10:33:23 pm »
That settles it then, thank you.
Assembly is the high level programming for an ASIC design engineer (with no VHDL/Verilog).
 


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