Odessa, sound like you are a novice and so am I. Let me share some novice's thought with you.
I thought about this a lot when I was learning the ADC. Then, I finally realized that for the 10 bit ADC, 1024 vs 1023 as the denominator really doesn't make much difference in the end. 1023 vs 1024 is ~0.1% difference. Most of my other stuff feeding into the ADC are at best 1% parts. Worrying about 0.1% with the denominator doesn't make much sense - I went with 1024 for easy division.
I mostly use ADC with my ATMega/Arduino. My bigger headache with the ADC reading is the power source - it makes a hell of a lot bigger difference than 1%. Beside load variation, I have the USB supplying anywhere between 4.7V to 5.2V depending on which machine/port I plug it into. Beside, when USB powered, the "source selector" diode alone ensured that you don't get 5V at the MCU except cases of extreme good luck.
After a while of learning, for situations where I like to have good ADC accuracy, I do the ADC and the math entirely differently: 1% TL431 is cheap. I use a dedicated TL431 connected only to ADC0 to give me 2.5V at ADC0, I use the other ADC to measure my target. All ADC reads begin with reading ADC0 first then the target ADC.
My math for the other ADC becomes: Voltage = 2.5V * ADCnReading / ADC0Reading.
For example:
if ADC0 (the TL431 at 2.5V) reads 500, and ADC1 reads 600, that means ADC 1 is reading (2.5V*600/500)
With that implementation, I can switch NANO/UNO power source and/or varies the loads powered by the Arduino all the while hardly affecting the ADC reading.
You may ask, why not feed the TL431's 2.5V into the ADC's vref directly. Feeding the TL431 into Vref mean that my ADC goes up to 2.5V only. Everything on my Arduino-powered circuit will need a voltage divider for measurement if they are >2.5V. Whereas, feeding it into ADC0 this way, everything else I need to measure can go to board's +5V (or whatever it actually is, be it 4.5V or 5.4V, I am still having a good time).
Of course, most of the folks here being pros, that is probably merely an obvious solution. Me being a mere hobbyist and a novice, I was actually rather pleased with myself figuring out that solution and made that work.