The circuitlab drawing of the circuit is a "live" URL. I should have taken a static png image instead. Anyway I updated it so you can refer back a few posts to see the update where I added R3 = 1r.
In that configuration, the total source impedance seen by U1 is 953r, implying it would be 952r without R3. Because R3 is just in series with the rest of the resistance, it simply adds to it and essentially doesn't change how R1+R2 interacts with R_IN. So I don't understand when you say, the interaction is small because of the low output impedance. No matter how small we make the output impedance (down to 0), the R_IN and R1+R2 interaction is the same. If the output impedance were very large, then in that case any R_IN vs R1+R2 interaction would still be there but would be irrelevant because the output impedance dominates.
I'll note that if I change the output impedance in the U1 model, rather than via the external R3 resistor, there's zero effect on the output voltage or current.
The CL simulation seems to confirm my thought, that the total load seen by U1 isn't just R_IN, which is what all the tutorial material on the web suggests. I suppose that the source impedance of U2 is in fact just R_IN, but the source impedance of U2 isn't the entire story when it comes to the load seen by U1.
But I'm still curious to understand your statement about how the output impedance of U1 makes the interaction small.
Hi,
Are you talking about the output resistance of the first op amp? That's what i am talking about.
You start with an ideal op amp. That is where there is no input offset, zero output resistance.
You then add a small output resistor in series with the output of the ideal op amp, say 10 ohms.
You then take the output of the non ideal op amp to be the open end of the resistor you just added.
You then connect the 1k resistor and two 10k resistors to the open end of the small resistor, and that end also becomes your new 'real' output. You then consider how the voltage changes as you change something else like the two 10k resistors, the 1k, or the 10 ohm resistor, at a convenient non zero operating point. The internal gain of the ideal op amp must also be finite, not infinite, such as 100 to 100000.
If this isnt clear or doesnt make sense or some other problem, i'll draw up a circuit and throw a few calculations out there for you to examine.
If i understand you right you want to understand the loading effect of the 1k and two 10k resistors right?