I was just wondering what you do to the common mode inductors when you (relatively) instantly reverse the current in them rather than the leisurely sine they are designed for.
Good question, please correct me cause I am not an expert at this but I would think that there is a small (time) gap for the relay contact to switch from AC1 to AC2,
so lets assume that the switching of the relay between contacts will take 10ms?
The step would be as suggested (worst case) so AC1 at -325V and AC2 at 325V (Vtt for 230VAC)
t=0ms -325V t=1ms 0V (contact open) t=10ms 325V from the input side.
Now with normal mains so no switching:
t=0ms -325V t=5ms 0V t=10ms 325V
The difference is that without switching the voltage will in the mean time gradually change and with the switching it will be two hard steps but I would think this is not different than switching it on from power off to power on at the voltage peak.
No idea what the CM inductors will do, although pretty small they would like to keep the voltage equal if i remember correctly, but since there is no mains input for almost 10ms they will be drained by the load or not?
Please fill in or correct me where wrong, I also would like to learn