I've been having some issues with calculating the equivalent circuits for the problem above, I've attempted it and included my calculations where possible.
So far I have calculated that 50ohm//50ohm = 25ohm
Therefore for Norton we have a 2A source and a 25ohm resistor.
Then I’m using
voltage = current x resistance to work out the voltage of the circuit so 2 x 25ohm = 50 volts.
So for Thevenin we have a 50 volt source and a 25ohm resistor.
The issue is when I use this site:
http://hyperphysics.phy-astr.gsu.edu/hbase/electric/thevenin.htmlto verify my answer.
With the input of 50ohm, 50ohm and 0.00001ohm (because it only calculates for a three resistor circuit) it returns an:
Open circuit voltage: 10v
Thevenin resistance of: 50ohm
So I'm not sure if this is correct because neither the book or my lecturer explained it very well. I managed to calculate a standard 3 resistor, 1 battery circuit but this one has stumped me!
Someone else insisted that these resistors were actually in series (not parallel as I assumed) and that they are used to calculate R
th but not V
th which I think has also caused me a little bit of confusion, so any help would be beneficial!