Transistor problem

[crash2140]

So, I've got this exercise I can't solve, and I would appreciate your help.
It says: "Polarize the transistor BC547 in the active region, with voltage divider in the base, determining the commercial values of Rb1,Rb2,Re and Rc"(sorry for the possibly wrong translation).
I've tried several methods and searched around, but it seems that I have to set a value for Re, and from there deduce the rest.
Thanks for your attention.

[DIPLover]

Please post what you have tried and why it doesn't work.

[crash2140]

Sorry, forgot to mention some information:
Vcc=10V
Ic=5mA
Vce=5V
Vbe=0.6V
hfe=110

[crash2140]

Using Thévenin's theorem, I got to these two equations:
10=0.005*Rc+5+0.005*Re
(10*R2)/(R1+R2)=[(R1*R2)/(R1+R2)*(45e-6)]+0.6+0.005*Re

[Richard Head]

You have to choose a voltage across Re. Normally it's about 2xVbe.

[dannyf]

The collector typically sets at 1/2Vcc for maximum swing.

So Ic * Rc = Vcc/2 -> solve for Rc.

Once Rc is solved, you can solve for Re.

Once Re is solved, you know Vb.

From that, you can find Rb2/(Rb1+Rb2). Typically their values are chosen so Ib is negligible.

Done.

[crash2140]

Ok thanks for helping out!

[IonizedGears]

Also just to add something,  this circuit was designed so that hfe was irrelevant.

~Ionized Gears