If this was an easy problem to solve, with a universally correct answer, they would have told us in the first week of EE school and we could have taken the next 4 years off.
You need to use the formula to find the MINIMUM driving impedance necessary for the operating conditions. If the conditions change, the result of the calculation changes. As has been pointed out above, this type of voltage divider is FAR LESS than a good idea because the parallel combination of the bottom divider resistor and the ADC input impedance changes with the conditions. This means that the voltage divider ratio changes with the operating conditions. So, not knowing the operating conditions means you can't solve the equation and, therefore, you can't come up with an appropriate divider.
But that's a good thing because the divider is doing nothing for accuracy. Furthermore, your sensor may not want to drive a relatively low impedance divider. Or, it might not be able to achieve accuracy driving it.
What you really want to do is use a 3.3V rail-to-rail input-output op amp between your sensor and the ADC. The sensor will see an essentially infinite load impedance (no current flow) and the ADC will see essentially a zero ohm driving impedance. It doesn't get any better than this!
If you don't know the operating conditions of the ADC, you should be looking into it. It all comes down to accuracy. If you don't need accuracy, any pair of resistors will do something. It won't be right, of course, but you will get results similar to what the folks on the Internet are getting.
Excel can do the calculations for the driving impedance (sensor) feeding into the divider with the parallel bottom resistor. Then you can iterate over sensor voltage and see what kind of graph you get. You could also model it in LTspice. But sooner or later, you're going to need to know the operating conditions.
ETA: The operating condition (frequency of conversions) could be as simple as "every time I loop through this C code, I grab one sample". If so, the calculation could be quite simple. Where the formula is really important is when you are taking periodic readings at a fast rate. Maybe a timer kicks off readings and the DMA channel stuffs them into memory. That might be a lot faster cycle.