Here's where the confusion starts:
Why R7 and C4 are connected to -VSS at all is somewhat of mystery to me, perhaps because of the lack of a designated return path connection.
The 78L12 circuit has only one connection to the adjacent circuitry, so it is inactive, floating, really floating. You mention a connection to a MCU, but connecting an output pin of an MCU directly to the electrolytic cap would not work well with the MCU without a current limiting resistor and the resistor values you have set here are quite low and would require a even lower resistor from an output pin to the base, overloading the MCU output pin current limit, but you still have the floating problem, you haven't designated the return path (MCU ground) to the MCU control pin circuit clearly(though it is easy enough for me to guess.)
R6 would, without MCU intervention, activate the relay (if there was a designated ground reference point..I assume it is negative terminal of the 78L12) and it would be the job of the MCU to pull down this current current and this requires a small-valued current limiting resistor to the MCU pin and yet it must pull the base voltage below .6V and this is also troublesome because of the large capacitor on the base.
If you have approx 11.3V across the 561 ohm resistor the MCU pin would have to sink >20mA and also discharge the capacitor through a current limiting resistor. So the resistor would be very small an value to pull the base below.66V and the MCU pin would be overloaded trying to discharge the capacitor upon instantaneous activation of the pin(probably causing it to switch from 0 to 1 state), but trying to fix this by increasing the MCU output control pin resistor would not pull the base below .7V to shut off the relay.
The relay could be just as easily be connected to the main high power transformer rectifier-filter cap + power point with perhaps just a current limiting resistor and a simple npn transistor to activate the relay, base of npn transistor to MCU output pin, emitter to ground.
Perhaps I am just a beginner, but I cannot see there is really a need for the 78L12 or two secondary transformer windings just to have a power source to operate the relay.
Also, C1 is a 104 that just .1uF not enough capacitance to accomplish anything to prevent arcing of the relay where it is placed, but there should maybe be two, both on the transformer side of the relay to help absorb the inductive kick, because that is where the inductance is.
R5 is probably not serving any useful purpose(except as a bleeder) and it must be several watts in size to prevent it from burning up.
C3 is only .1 uF, a rather very small output filer capacitor for a power supply.
R1 and R2 are attenuating the gain of the regulating or control circuit you are attempting to create here. Rather ingenious but perhaps not optimal strategy to accomplish something that is perhaps not quite obvious to me.
If R1 is to connect to a circuit to control the output of the power transistor, then it must be supplied with a voltage that is always slightly higher than the output of the supply..not quite clear how efficient this circuit is to do this, I donno how well this circuit configuration might accomplish this with what I see here, considering the R1 attenuating resistor. I can't see how you get this control voltage.
Maybe I am just a beginner here, not seeing the big picture, the whole schematic.