Author Topic: Why should analog ground and digital ground be separated in some instrumentation  (Read 2084 times)

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Offline nourTopic starter

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I have noticed that in a lot of instrumentations, the ground of the analog part and the digital part are usually separated and also the connection between them(control and data transfer) are usually separated by optocouplers? Why?

Why does the ground should be separated and why they use optocoupler also between them?
if what I have wrote doesn't make sense for you or you think there is something wrong, please correct me, I am still beginner and what I know probably less than what you know
 

Offline Ghydda

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I have noticed that in a lot of instrumentations, the ground of the analog part and the digital part are usually separated and also the connection between them(control and data transfer) are usually separated by optocouplers? Why?

Why does the ground should be separated and why they use optocoupler also between them?
The short answer is proberbly: to ensure/control the path of each sections return current.

If two subcircuits share return current path or have crossing return current paths, they will interact.
Usually this is okay for most circuits, but when high precision or low noise must be achieved, then completely separating the return currents is the way to go.

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Offline tablatronix

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My understanding is I thought it was because digital is high speed and induces noise into the analog stuff, opamps filters etc. so keeping power seperate allows better filtering and isolation. I could be totally wrong.
 

Offline Bud

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Ground partitioning may be difficult to figure out when using 'hybrid' devices such as DDS ICs that have both digital and analog circuits inside. I stopped worrying about it after speaking to a engineer at Analog Devices who said they do not use separate grounds in the Lab and when characterizing their products.
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Offline danadak

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Love Cypress PSOC, ATTiny, Bit Slice, OpAmps, Oscilloscopes, and Analog Gurus like Pease, Miller, Widlar, Dobkin, obsessed with being an engineer
 
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Offline German_EE

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A practical example.

I have on my bench at the moment a phased locked loop that covers 35 MHz to 75 MHz in 0.1 Hz steps. The VCO sensitivity is 3.5 MHz/V or (and this is where it gets interesting)  3.5 Hz per microvolt. So, if I change from 40.0000001 MHz to 40.0 MHz the VCO voltage has just dropped 29 nV, not a lot. If the 3.3V control logic was sharing the same groundplane*** as the VCO the switching noise would modulate the VCO input and I would not have a very good synthesizer.

*** Note that no groundplane is perfect, it has inductance and resistance and therefore has circulating currents.
Should you find yourself in a chronically leaking boat, energy devoted to changing vessels is likely to be more productive than energy devoted to patching leaks.

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