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Footprint with two equivalent pins problem
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ale500
Frequent Contributor
Posts: 415
Footprint with two equivalent pins problem
«
on:
May 12, 2018, 06:35:00 am »
I want to define a footprint with 3 pins, two of them are equivalent meaning I can connect on the pcb to any of them, they are connected internally.
I defined a footprint that has 3 pads and numbered two of them with the same number "2". I assign this foot print to an existing component that has two pins and connect these two pins in the circuit (it is a button).
The problem is that pcbnew still shows the airwires to the "unconnected" second pin (also numbered 2).
Is there another setting that I have to apply to tell it that connecting to any of these pins is enough ?
ANother related question: if I update a footprint how do I tell pcbnew to re-read the library ?
thanks
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Rerouter
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Question Everything... Except This Statement
Re: Footprint with two equivalent pins problem
«
Reply #1 on:
May 12, 2018, 07:10:17 am »
In general i would assign them different pin numbers, and just reverse them as needed, If you make clear in your schematic icon that either orientation is fine, its just a case of flipping the component, updating the netlist and re-reading in pcbnew
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hermit
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Re: Footprint with two equivalent pins problem
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Reply #2 on:
May 12, 2018, 03:25:16 pm »
Last I knew you could not connect pins in the footprint. I'm not sure if this will change in V5. As far as I know you just connect them in the schematic and live with the DRC errors.
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Footprint with two equivalent pins problem
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