Hello all,
I am confused with selecting External load capacitor for Crystal(ABM3B-8.000MHZ-10-1-U-T )which have load capacitance of 10pF.Right now, I have used 10pF as external load capacitors in My circuit.But, Atmel says that to use the following formula to calculate external load capacitor..
CLEXT = 2(CL – CSTRAY – CSHUNT)
Where :
CL =10pF= Crystal Load capacitance. The value of CL can be found in crystal datasheet
CSTRAY = Parasitic Capacitance of the crystal pins ( XIN, XOUT) and PCB
CSHUNT =3 to 7pF= Shunt capacitance of the crystal
CSTRAY = [(CXIN * CXOUT) / (CXIN + CXOUT)] + CPCB
As per SAM L21 device datasheet, CXIN = 5.8pF, CXOUT = 3.2pF
Parasitic Capacitance (CPCB) of PCB is 0.5pF
External capacitor value after formula:
CSTRAY = [(5.9pF * 3.2pF) / (5.9pF + 3.2pF)] + 0.5pF = 2.5pF
CLEXT = 2(10pF – 2.5pF - 7pF) = 1pF
So, Should I change My external load capacitor from 10pF to 1pF?
Please suggest..
Thanks,
Sangar