Author Topic: GFSK deviation and baudrate  (Read 3065 times)

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Offline qsdrTopic starter

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GFSK deviation and baudrate
« on: April 23, 2014, 11:48:26 am »
Hi,

What is the relation between the frequency deviation and the baud rate in the GFSK modulation?

 

Offline VK5RC

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Re: GFSK deviation and baudrate
« Reply #1 on: April 23, 2014, 11:52:23 am »
Doesn't the Hartley Shannon theory relate the two (frequency deviation equiv to channel bandwidth) directly along with the signal to noise ratio of the channel?
PS One of the Agilent App Notes has a nice graph of some of the limits of digital comms along with signal to noise. http://cp.literature.agilent.com/litweb/pdf/5952-8255E.pdf
« Last Edit: April 23, 2014, 11:56:20 am by VK5RC »
Whoah! Watch where that landed we might need it later.
 

Offline qsdrTopic starter

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Re: GFSK deviation and baudrate
« Reply #2 on: April 23, 2014, 03:47:21 pm »
The Hartly Shannon theorem is fp <= 2BW, with BW is the band width and fp is the pulse frequency.
But for the GFSK modulation I found the following theorem: BW = 2Fd + Rb, with Fd is the Frequency deviation and Rb the data rate. So what is the relation between this two rules?
In other side, what is the rules to chose correctly the baud rate and the frequency deviation to have the best distance range.
 


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