well, maybe I'm being thick, but I still just cannot figure what you are trying to do here.
The + input of the op amp sits at +12V, more or less. The op amp tries to keep the negative input the same. This means that current will flow through the LED's and the 10k resistor, so the op amp will simply swing its output towards ground to give that current somewhere to go. A tiny amount (typically nA, I didn't look up this op amp) will actually go into the ive pin, but that is negligible. Most current will simply flow into the op of the op amp, which will cause the LEDs to come on a bit, depending on the number of LED's. Even if the FET is off.
When the FET is on, the o/p of the opamp swings high because the FET drain goes pretty much to ground. But - how is the current for the LED's set? is there some feedback to the FET gate? as far as I can see, if you switch the FET hard on, you will probably burn out either the FET of a LED.
Are you trying to make some kind of fancy current source? or sense if the FET is on? or control brightness? what exactly?
Maybe there is method in this that I am not seeing, but my gut feeling here is that whatever you are trying to do, there is a better way.
(edit : as you have drawn it, with the FET off, I would expect to see roughly 10V across the 4 LED's, which means the 10k resistor has about 2V across, pulling about 0.2mA through the LEDs, which will therefore be dimly on. The output of the op amp will sit at about 10V or so.)