Yeah, another one.
I need a low voltage cutoff circuit that you can enable after the battery has been connected and latches off once the threshold has been crossed. Then, draws absolutely minimal current as it may be a few months before I can get to the thing to take the battery out. The battery will be charged on its own.
I've attached two slightly different schematics of something I'm messing about with.
I have built both and the first one (sch0) works as I'd expect if C3 is fitted, not if it isn't. The second, sch1, well I'll get on to that.
It's a pretty straightforward comparator circuit but I've moved the "measure" or "sense" element to the other side of the output FET, which works as a latch. The idea is that once the FET turns off, the sensed voltage is hopefully very low, which keeps the FET off. This does work quite nicely on the real thing.
The reed switch is the "enable" device. Without C3 fitted, the FET conducts as soon as you connect J1 (the input) to the power supply, whether the reed switch contacts are closed or not. I haven't had a chance to play around with values of C3 yet.
Well what I'd really like to do is move everything to the right of the MOSFET apart from R6. I tried this in "sch1" but now the thing really is always on as soon as you connect the battery. The comparator has a push/pull output stage - not sure an open collector stage will help me as I have mulled it over and have come to the conclusion that it's the low side doing it.
I'm going to get this on an oscilloscope tomorrow to try and capture what's going on at startup but I thought I'd ask here if anyone has tried this before.
A thought I had whilst driving home is that if the FET even starts conducting slightly, it will start doing a comparison and then the output of the comparator , which is trying to drive high relative to the low supply voltage, will end up pulling Q1 down.
Any ideas would be great - someone must have done this before... Thanks in advance.