As promised, here are the numbers:
Taking into account 600RM.....and the most significant drag components to maintain operation of the motor, I came up with 1.176mw.
The total time the motor can run from a fully charged battery is about 166 hours.
Here is the math:
T= Torque in Newton-meters (for a single cylinder) = (p*Cd*x*W^2xR^4)/8
TT = Total-Torque = T*6 <----There are 6 "cylinders"
Within the equation, the below constants and variables are already known:
R is distance from the edge of the armature magnet to the center.
Cd is drag coefficient of a cylinder (smooth) = 1.17 ...at sea-level @70-deg.
x is diameter of the magnet
W is Angular Velocity (in radians/second) = 2x(Pi)xRPS
where RPS= RPM/60
p=fluid(air at sea-level 70 degrees actually) drag density constant.
p = 1.2 kg/m^3 Which gives:
T = [1.2 * 1.17 * x * W^2 * R^4]/8
TT = 6T
Energy (watts) = (TT x W)
Here are the numbers for 6 poles with diameter of the magnet and length from center of rotor to TOP of magnet.
The constants:
Cd=1.17
p=1.2
The motor's rotor properties
Steady-state RPM=600, giving W=62.8
R=.02857m
x=.0127m
T = [1.2 * 1.17 * .0127 * 62.8^2 * .02857^4]/8 = .0000058566 Newton/Meters
TT = 6T =.00003514 Newton/Meters
E1=TT*W = 2.21mw
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Here are the numbers with diameter of the magnet and length from center of rotor to BOTTOM of magnet.
The constants:
Cd=1.17
p=1.2
The motor's rotor properties
Steady-state RPM=600, giving W=62.8
R=0.02540m
x=.0127m
T = [1.2 * 1.17 * .0127 * 62.8^2 * .0254^4]/8 = .000003659 Newton/Meters
TT = 6T =.00002195 Newton/Meters
E2=TT*W = 1.3786mw
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Here are the numbers for 6 poles with diameter of the screw (which magnet mounts to) and length from center of rotor to BOTTOM of magnet.
The constants:
Cd=1.17
p=1.2
The motor's rotor properties
Steady-state RPM=600, giving W=62.8
R=0.02540m
x=0.003175m
T = [1.2 * 1.17 * .003175 * 62.8^2 * .0254^4]/8 = .000000915 Newton/Meters
TT = 6T =.000005488 Newton/Meters
E3=TT*W = 0.34465mw
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Total energy required to spin rotor @600RPM TE is:
TE=energy of magnet + energy of mounting screws
TE= (E1-E2)+E3
TE= (2.21 - 1.3786) + .34465 = 1.176mw
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Total battery energy available:
Here are the constants:
1.3v nominal voltage capacity under very light load
150ma/hr capacity
Which gives: 195mw/hrs of energy total.
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How many hours of run time:
195mw/hrs/1.176mw = 165.82 hours.
It is much lower if I factor in significant electrical losses (.5 volt drop across the switching bipolar transistor junction being the biggest).
PS: Another thumbs-down on the video? I figured I'd snag a few people who could not sort this out.