The one and only correct size is 0.05" (if that doesn't fit it is likely to be imperial). Be sure to get a good quality set though because you may need some force which could break a cheap allen key or worse: ruin the screw.
That is worth repeating. On larger sizes the quality of the steel and the preciseness of fit are not terrible critical. But the smaller size screws are worked much closer to their limits and you can easily be frustrated as your tool rounds off, or infuriated as the tool rounds out the inside of the screw without removing it.
Easy outs for these sizes don't work either so when you round them out you are either done or drilling them out and starting over.
I'd go the other way and say that it's not
if you are going to strip the tools or the screw, it is
when. It doesn't matter how good the materials or how well the tools are wielded, tiny hex sockets are always going to be working close to the material's shear strength. Anybody who designs something with such tiny hex sockets should be repeatedly kicked in the unmentionables until their ears bleed.
I just did a back of a cigarette packet calculation on this, and it's a web of material a mere 0.0077" thick that's taking the strain on a 0.050" socket. An generous estimate of the socket depth is 1/16, so that's 0.0077 * 1/16 * 6 = 0.0029 square inches of metal taking the load (probably less in practice). That gives a yield point of around 230 lbf for grade 5 bolt steel (81,000 psi yield strength, 105 kPSI UTS), at the end of a lever that must be multiplying force by 100 (2.5 in wrench, 0.025 in radius head), so just 2.3 lbf on the end of the Allen key to permanently deform the socket, 3 lbf to completely round it off. That's assuming that all the force gets applied evenly, in practice I suspect the edges of the Allen key act more like a very blunt cutting tool. Memo to self: stick some penetrating oil on these grubs screws the night before trying to remove them.