Ok so my hunch was right, the MB10F is a rectifier diode, and the large cap is probably smoothing out ripple current. ES1J is a fast rectifier. The main IC on there is HA5832E is an efficient LED constant current controller power supply translated from Chinese as follows:
"HA5832E is a high-precision non-isolated step-down LED controller, anti-flicker, for 85V ~ 265V full voltage range of low power Non-isolated step-down LED lighting applications HA5832E built-in high-precision sampling, compensation circuit, so that the circuit can achieve ± 5% or less constant current accuracy, and can achieve output Current to the inductor and the output voltage of the adaptive, so as to achieve excellent linear adjustment and load regulation HA5832E internal integrated 500V power MOSFET, no secondary feedback circuit, and no compensation circuit, coupled with accurate and stable self-adaptation Should be the technology, making the system is very simple external structure, the number of peripheral devices in a small number of parameters under the conditions of loose to achieve high precision constant flow control System, which greatly saves the system cost and volume, and can ensure that in mass production LED lamp parameters of the consistency HA5832E has a wealth of protection: output open short circuit protection, sampling resistor open short circuit protection, undervoltage protection, output overvoltage protection, too Temperature adaptive adjustment and so on."
I just noticed a spot on the board that says RS1 (next to the HA5832E chip and the blue resistor) seems unpopulated, as if an SMD component should be across there. Then again, there is RS2 and RS3 also written and I'm not sure what it is referring to. The other SMD resistors are listed just R1, R2, R3, so not sure what RS is supposed to be. Also one of the pads for the HA832E chip is not used (no solder). I don't think any of this has to do with the flickering bulb but just an observation on the design of the board.
Previously in the thread someone mentioned 3.3V or 6.6V per LED, and there are 9 LED. The LED board says "27mm8W9LED" which I assume to mean it consumes 8 watt. They appear to be in series which means if we chain 9 together the voltage drop is either 29.7V (if each is 3.3) or 59.4V (if they are 6.6). So does that mean we need 269 mA (if they are 3.3 V LED) or 134 mA (if 6.6V) current driving the circuit?