Electronics > Beginners
10A Fuse on Multimeter
skillz21:
I have a multimeter, and for its current measurement, it says it has a 10A fuse. On the back of the multimeter, it says that it contains 2 fuses, one rated for 600v 10A and another rated for 200mA 600v. For this question, I'm going to focus on the 10A fuse. I'm kinda confused about this. Wouldn't you need 6000 watts to blow that fuse? Because technically, isn't it the watts that determine how much heat something is going to create? Or am I very wrong? So wouldn't I, theoretically, be able to measure more than 10 amps? (this doesn't mean that I'm going to, the wires get pretty warm around 8 amps.
skillz21:
--- Quote from: tvl on January 08, 2019, 09:02:38 pm ---Just to chime in:
Current X Voltage Equals Watts
Therefore, you have a meter in series with a specific load for current measurement. The voltage on the circuit is 120 volts AC and in my theoretical case the load happens to pull 10 amps: 120 VAC X 10 I = 1200 watts
Were you possibly thinking about a measurement on a circuit with 600 volts (WOW!) 600 Volts X 10 I = 6,000 Watts Of course, in this case, the fuse was blown very, very quickly!
--- End quote ---
I understand that, yes. Could you please explain to me why the fuse would be blown at 600v 10A? I don't understand, it says it's rated for 600v 10A(that equals 6000w)...? (yeah I understand that 6000 watts is a crazy high number, that what I'm trying to make sense of here.
cowana:
The fuse is rated for 10A current. Above that (ignoring the time it actually takes), it will blow. Doesn't matter at all about the voltage.
Note that because of the thermal mass of the fuse, it won't instantly blow at 10.001A - the time taken will depend on the current. It can likely survive 15A for several seconds.
When it does blow, it will create an open-circuit. It can then cope with up to 600V across it, before it will begin to arc and conduct again (not properly breaking the circuit). Below this 600V limit, it should be fine. This is why fuses have a voltage rating - it just doesn't apply until it blows.
barry14:
You are misinterpreting the fuse specification. A fuse rated for 600 volts and 10 amperes will blow when the current through it reaches about 10 amperes irregardless of the voltage of the source feeding it (fuses are not precision devices). Once the fuse blows, it is able to withstand up to 600 volts across it without shorting or arcing. The fuse will never see 600 volts across it and 10 amperes through it (at least not for long).
rsjsouza:
--- Quote from: skillz21 on January 08, 2019, 08:49:56 pm ---I have a multimeter, and for its current measurement, it says it has a 10A fuse. On the back of the multimeter, it says that it contains 2 fuses, one rated for 600v 10A and another rated for 200mA 600v. For this question, I'm going to focus on the 10A fuse. I'm kinda confused about this. Wouldn't you need 6000 watts to blow that fuse? Because technically, isn't it the watts that determine how much heat something is going to create? Or am I very wrong? So wouldn't I, theoretically, be able to measure more than 10 amps? (this doesn't mean that I'm going to, the wires get pretty warm around 8 amps.
--- End quote ---
The meter (and consequently the fuse) is placed in series with the load. In this condition the voltage across the meter and the fuse is very minimal as the fuse has a very small resistance. For example, if the fuse has 0.005Ω of resistance and the current flowing through it is 10A, the voltage across the meter would be: V = R×I => V = 0.005×10 => V = 0.05V. Consequently, the power dissipated on the fuse would be P= V×I => P = 0.5W
In case of an overcurrent event the fuse opens and stays opened, thus the entire supply voltage is present across the meter (and the fuse) terminals. The voltage rating of the fuse expresses how much voltage it can safely sustain across its terminals if interrupted.
The 6000W you calculated would be only present on the load under test, if the supply is 600V @ 10A.
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