Let's keep it practical here. He has an external cabinet 4 Speakers each of 16 ohms. 4 X 12" being common as are 4 X 10". No switching averaging 80%/20% or whatever idea is practical and his keyboard/guitar amplifier head would look at that crazy cludge and just go nuts. Totally impractical for a gig amp on stage. Also, a transformer that works at stage volume and can sound good passing the heavily distorted guitar waveshapes without showing coloring of the sound or looking like a dead short during the flat-topped portions of the waveshape also won't be found and if you could it would be heavy and just another burden of weight to lug around to the next gig. Remember a speaker during flat topping still shows a great deal of resistance, about 80% of the marked impedance in fact. Not so with transformers in that power range, probably under 1/2 ohm max. As for modding the speakers....a very easy chore. The typical wiring is either 2 X 16 in parallel giving 8 ohms, in series with an identical pair giving 16 ohms total OR all 4 X 16 ohm speakers in parallel giving 4 ohms. Incredibly easy to change the wiring since in 99% of the cases the speakers are connected with spade lug wiring and the only difference between the 16 ohm and 4 ohm cabinet when they left the factory was which way the wires were connected. They DID NOT use different part number wiring harnesses, they simply connected the harness (mostly 15" long wires with female spades on each end) differently. The end user can mod the cabinet in under 1/2 hour at zero cost and zero weight gain......but, sady, your choice is 16 ohms or 4 ohms UNLESS you buy 4X 8 ohm speakers Which many people do after blowing up the 16 ohm originals.
Hello there,
From your reply it sounds like you have never done an averaging analysis. If you think it is not practical, then you must be rejecting one of the most modern designs for an audio amplifier which is the class D type amplifier. I am not exactly sure why you reject that, maybe you just don't like switching circuits because they sound too complicated, but really there is a lot of theory in this area.
Just for a basic idea, if you had a 10 Ohm resistor and you switched it on and off with a 50 percent duty cycle, the circuit driving that resistor would see a resistance of 20 Ohms on average. If you change the duty cycle to 33.3 percent, it would look like a 30 Ohm resistor.
That's just a brief look into this but of course there is a little more to it than that. The driver has to be able to work with a switched resistance. That means it must be able to handle that 10 Ohm resistor for whatever percent of the time it has to be 'on'. Because the main load is not 'on' all the time that means this would come with a loss of power which can be significant or not depending on the application.
There are other solutions too though that are much simpler, but with a loss of power.
For example, four 16 Ohm resistors in parallel also in series with a 4 Ohm fixed resistor. This makes the total resistance 8 Ohm although there will be a power loss of 50 percent which may or may not make a difference.
For two sets of two in series also in parallel with each other, the total resistance is 16 Ohms, and using a 16 Ohm fixed resistor in parallel with that set brings the total resistance seen by the driver to 8 Ohms. Again though we have a power loss of 50 percent.
The solutions above come up when the user is limited to what they have and what they can get. Obviously if they can get an 8 Ohm speaker that handles the whole power we wouldn't be here. When limited to what we have on hand though, we have to improvise.
If none of the other solutions are acceptable then that's just the way it goes. If also the 4 Ohm or 16 Ohm simpler solution is not acceptable then buy something that is acceptable.