Connecting the LED from pin 3 to +V, rather than 0V, as I said before, will help the output swing to near +V into a CMOS input, but it will invert the LED output.
The output pin charging/discharging the capacitor doesn't work quite so well with the bipolar 555 timer and is marginal, with the LED connected between the output and 0V.
Good point about pin 7: R1 = 1k and R2 = 10k, so the 4026 input could be connected to pin 7, with no other modifications to the circuit. When pin 7 is low, it will be close to 0V and when pin 7 is open, and the voltage across the capacitor is 1∕3Vcc, it will be:
Vhigh = Vcc-R1*(Vcc*2∕3)/(R1+R2) = 5-1*(5*0.6667)/(1+10) = 5-3.333*11 = 4.7V
Which is well within the CMOS voltage thresholds.