I am familiar with the concept of an AC signal riding above a DC voltage. In such a case the DC component can be filtered out through a capacitor, or using the AC coupling mode on the scope, in which case the resulting waveform would be an AC signal centered on ground. I would have thought I would get the same result if the DC component is removed altogether. But when a sine wave generated by my signal generator is fed directly to my scope, the waveform is entirely BELOW ground, as can be seen in the picture. Can someone please tell me why that is?