Hello,
I have been experimenting with discrete BJT RF amplifiers, and have one based on MPSH10 with a high input impedance Zin.
If I want to get a 50 ohm input impedance, I could put a feedback resistor between output and input, as in this circuit:
As I have understood, applying Miller´s theorem this is equivalent to an impedance of \$Z=\frac{Rf}{1-Av}\$ in parallel with Zin. If the gain Av is negative (inverting amplifier) and I choose Av and Rf conveniently, this Z can be 50 ohm, which in parallel with Zin is still 50 ohm.
Indeed, if I do this in LTspice, I get the following input impedance of the amplifier:
My question is why would I do this (taking into account that the input impedance soon deviates from 50 ohm, as seen above, and this method reduces the gain, as there is a second impedance in parallel with Rl). Instead, I could simply put a 50 ohm resistor at the input, in parallel with Zin, with no gain loss and the following resulting input impedance:
I fail to see the problem in this second simpler method. The input power would be wasted in this input resistor, but this is also the case in the feedback resistor method, I think. What do you think?