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AMR sensor circuit explanation
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nForce:
I don't understand this circuit in attachment. What does that integrator do in feedback?

Can someone explain slow and in detail. I know what is an AMR sensor and Wheatstone bridge I just don't understand the outside circuitry.
station240:
There is an explanation of how this exact circuit works here.
http://archives.sensorsmag.com/articles/0399/0399_18/index.htm

The integrator in the feedback path, is there to remove DC offsets caused by the circuit itself (especially the opamps), so the reading is relative to 0.
I'm sure someone else can better explain the rest of the circuit, it's really late where I am.

nForce:
Thanks, but why is the integrator connected to the non-inverting input of the other op amp? Shouldn't be to the inverting, because we want negative feedback?

Do you maybe know what does that not gate with the capacitor do?

Thanks again.
Benta:

--- Quote from: nForce on October 18, 2018, 04:09:29 pm ---Thanks, but why is the integrator connected to the non-inverting input of the other op amp? Shouldn't be to the inverting, because we want negative feedback?


--- End quote ---

The integrator has negative gain, which is why it has to go to the non-inverting input. Otherwise you'd have negative x negative = positive feedback.
nForce:
Thanks Benta, do you know:


--- Quote ---what does that not gate with the capacitor do?
--- End quote ---
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