Author Topic: Another LM338 related question  (Read 850 times)

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Offline the_eagleTopic starter

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Another LM338 related question
« on: July 14, 2021, 12:25:29 pm »
I am adventuring myself in the design of a 28VDC linear power supply (for the other specs of the power supply I am using as reference MIL-STD-704F).
AC mains (UK) is rectified from a 100VA transformer which gives an unregulated voltage of about 52VDC.

Because 52-28=24V, the continuous output current of the LM338 is limited to only 2A. Therefore I am thinking to shift the unregulated DC output from 0/52VDC to -17/35VDC such that Vout-Vin of the LM338 is less than 10V.

I have drawn a circuit in LTSpice which seems to give 28VDC output voltage, but when I add a load of 10 Ohm, the output voltage drops to 300mV. Why is this happening?

I am more than happy to do a complete change of the initial design

EDIT: confused Peak-to-Peak with Peak voltage. Removed transformer secondary voltage
« Last Edit: July 14, 2021, 12:45:06 pm by the_eagle »
 

Offline Circlotron

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Re: Another LM338 related question
« Reply #1 on: July 14, 2021, 12:34:24 pm »
As soon as you apply your load the voltage drop across R3 and R4 causes the input voltage to the regulator to drop to a very low value. Also, an 18VAC transformer should give you about 25.4V, varying somewhat with load.
 

Offline the_eagleTopic starter

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Re: Another LM338 related question
« Reply #2 on: July 14, 2021, 12:49:31 pm »
I was doing automatic conversions from rms to peak voltage but I didn't notice the result was peak-to-peak instead of Peak voltage.

Thank you for the explanation. What can I use as an alternative to the resistors?
 

Offline Circlotron

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Re: Another LM338 related question
« Reply #3 on: July 14, 2021, 01:07:35 pm »
I’d say use a 25vac transformer and no resistors.
 


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