*Skip the first paragraph if you're uninterested in my introduction, thanks.
Hi, I'm new here.
I'm a professional automotive mechanic looking to further my knowledge in electrical and electronics field. Considering the ubiquity of electronic systems in modern cars, I believe a thorough understanding in electronics is essential to improve my ability in auto diagnostics and repair. I know very little about electronics and wish we can learn together.
I'm planning of buying the Fluke 88V specialty automotive DMM and have a few questions
1. One of the function on the 88V that catch my interest is PWM measurement. But I was pondering, is it possible for us to calculate PWM based on frequency and duty cycle measurement?
2. The 88V is not a true rms multimeter. I wonder how the lack of trms will (or will not) affect its PWM readings? I learned that trms only applies to AC, but I read somewhere in this forum that DC can also benefit from trms capability when measuring PWM and logic signal.
3. Many multimeters can measure temperature with a thermocouple probe. Question is, is the thermocouple an indispensable component to make measurements? Can't I just use my test leads?
Just to clear things up:
- I already searched and asked these questions elsewhere with disappointing result.
- Yes, I need a Fluke. I've had experience where other brands gave me weird readings.
Thanks everyone.
Hi,
Are you talking about a square wave PWM or other?
The square wave or rectangular wave PWM is easy to understand, if it is not a square wave then it is a bit more difficult. Even a sine wave can have a non 50 percent duty cycle (positive half vs negative half cycles).
For a square wave PWM the average voltage is simply the pulse time high divided by the total time period, times the peak voltage.
For a non square wave it is the integral over the period divided by the period:
(1/T)*integrate(f(t),t,0,Tp)
where
f(t) is the wave to be measured,
t is time,
0 is the start time of one period,
Tp is the period time.
You do have to be careful though sometimes you have to integrate over each half cycle independently then add the results in recognition of the fact that areas are usually taken to be always positive. In cases of 50 percent duty cycle you can usually get away with integrating over just one half cycle then multiplying the result by two.
Example of a regular sine wave 50 percent duty cycle:
f(t)=Vp*sin(2*pi*f*t)
and with Vp=10 and f=100 we end up with:
f(t)=10*sin(200*pi*t)
and using floats:
f(t)=10.0*sin(628.3185307179587*t)
integrate over one half cycle which for 100Hz is 0.005 seconds:
a=integrate(f(t),t,0,0.005)
we get:
a=0.031830988618379
and then divide by the period which is the half cycle 0.005 seconds, we get:
Vavg=6.366197723675813
Note because we integrated over the half cycle using the half cycle period we get the average over one half cycle but since the other half is the same the entire average is as shown.
Note this is considered the average value of a sine wave but the mathematical average is zero because one half cycle cancels the other half cycle. In measurement theory the result either 6.366 volts or 0.000 volts is interpreted as dictated by the application. Usually power line measurements use the 6.366 volt measurement interpretation and this is what many regular AC volt meters would read. RMS volt meters would read 7.071 volts RMS because that is a different measurement and different calculation:
Vrms=sqrt( avg(f(t)^2) )
where
avg=(1/T)*integrate(F(t),t,0,Tp)
as before but f(t) is first squared so F(t)=f(t)^2.
The main difference is we first square the wave before taking the average, then take the average, then later take the square root. Hence the mnemonic RMS which is Root of the Mean of the Square, where Mean is another word for Average.
Also as before, for the regular sine wave we could do this over just one half cycle but because the wave is first squared we could also do it over an entire cycle without worries about the interpretation.