EEVblog Electronics Community Forum
Electronics => Beginners => Topic started by: Camelkos on September 29, 2020, 09:07:45 pm
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Hi Everybody,
Can someone please explain how we get this equation, frome this circuit thank you very much!!
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C1G does not play any role since it is connected directly to an ideal voltage source.
The rest of the components form a voltage divider. Upper part of the divider is C12. The lower part is the parallel of C2G and R.
If you represent R by ZR and 1/jwC with ZC you will have:
Vn=Vi(Zr//Zc2g)/((Zr//Zc2g)+Zc12)
The rest is a page of algebra which I'll leave to you. :)
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i think there's something wrong in what you wrote, can you please correct the equation
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Here you have the complete solution.
It could be shorter, I suppose. :)
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Thank you very Much !!