Zero, A bridge rectifier with filter bank looks hugely inductive!! Think about it, the voltage will rise until it begins to add current to the filter bank at its existing voltage level. So there may be no current flow until the voltage rises to 80% or more of the existing state of charge. So capacitive power factor correction makes sense. The way they implemented it is a piss poor design and destined to fail as it surely did. A back to back pair of polarized capacitors makes a damn poor non-polarized capacitor, especially for non-symetrical waveforms. Non-polarized capacitors from reputable manufacturers ARE NOT internally a pair of polarized capacitors although there have been examples of some garbage made that way,
I've thought about this more and no, it's not inductive either.
Both simulations are wrong. Replace the load with a zener diode and resistor to hold the voltage down to say, 12 to 14 volts with 1 volt of ripple.
Why?
We don't know what the load on the bridge rectifier is.
My suggestion my be wrong, but it's likely yours is too.
A constant load is correct, if it's a linear regulator, which is a constant current load.
A zener + resistor is correct, if it's a shunt regulator.
Add a resistance to the ac source such that you lose about 15% power in the resistor. Then sweep the capacitor or inductor. (After the inline resistor)
Fair point. 10m is probably much lower than the internal resistance of a small transformer. Increasing the series resistance, will reduce the current spikes and improve the power factor, at the expense of increased power loss.
Zero, A bridge rectifier with filter bank looks hugely inductive!! Think about it, the voltage will rise until it begins to add current to the filter bank at its existing voltage level. So there may be no current flow until the voltage rises to 80% or more of the existing state of charge. So capacitive power factor correction makes sense. The way they implemented it is a piss poor design and destined to fail as it surely did. A back to back pair of polarized capacitors makes a damn poor non-polarized capacitor, especially for non-symetrical waveforms. Non-polarized capacitors from reputable manufacturers ARE NOT internally a pair of polarized capacitors although there have been examples of some garbage made that way,
I've thought about this more and no, it's not inductive either.
In reality, a bridge rectifier and smoothing capacitor is neither capacitive, nor inductive. It's just non-linear.
I simulated this to prove it. Notice how adding an inductor or capacitor of different values doesn't reduce the current draw? All you get is the current spikes plus the additional current drawn by the inductor or capacitor.
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Conclusion: the capacitor in parallel doesn't do anything to improve the power factor of the bridge rectifier. If it did, then it would be very common, but it isn't.
Hi,
Sorry, but I do not see any place in that post where you are showing the power factor.
You've shown waveforms, but not the power factor.
It does not matter if the load is linear, nonlinear, or some combination, or spikes or no spikes, it only matters what the power factor is before and after the power factor adjustment component(s) are added. If the power factor improves, then it works, if it does not improve, then it does not work, and some other method must be used (if there actually is going to be any power factor correction for the circuit that is).
Note also that I am not sure if we can assume what the load is just yet.
This does not mean that your conclusion will not be right, it just means that you have not yet proved that because we don't see anything about power factor we just see waves.
There also remains some question about why they used such a poor method for connecting the capacitors together regardless of what they are supposed to be doing to improve the circuit.
It should be fairly obvious that the power factor is not improved by addition of L or C, by looking at the waves. If it was, then the current consumption would reduce, but that's clearly not what's happening.
For conclusive proof, the power can be calculated from the waveforms, which LTSpice can do, but I've not got time at the moment.