Hey guys,
I'm currently working with an ADC (the AD7982). It requires a fully differential input. For this, a previous engineer used the ADA4941. I'm currently trying to understand how it works, by modelling in LTSpice. The application note for the ADA4941 mentions that:

Referring to the circuit diagram:

My confusion is that I don't understand how there can be two common mode voltages, I thought the point of common mode meant it was
common to both. So, obviously there's something I'm not understanding.
The application note
https://www.analog.com/media/en/technical-documentation/application-notes/AN-1494.pdf gives two equations (the text preceding them is highlighted above). I've simulated the op-amps, and I can't get the values:
OUT_N,cm = 5*0.5 * 2 = 5V
OUT_P,cm = 5*0.5 = 2.5V
So, this says that the common mode voltage on the negative pin is 5V, and the the positive is 2.5V. With a 0V input voltage, OUT_N is 2.5, so I assume this is the common mode voltage their talking about, but it's on the wrong pin (negative, not the positive). But no matter what I probe, I can't see 5V referring to any of the output pins.
Can anyone explain to me the common mode voltage definition for this application? I'm only use to the definition (V1+V2)/2 as being the common voltage, but I don't think that works here.
Thanks guys, attached is the simulation if anyone wants to have a look.
Max