Last question first: the CM range on the input voltage is for both of them together. Your difference (V+ - V-) is the differential input voltage, and may not be so large as the CM range.
General answer: if you have any two voltages V1 and V2 with respect to a common reference node (e.g., ground or the negative supply voltage, as relevant), you can always define the common-mode and differential voltages
VCM = (V1 + V2)/2 for the common-mode, and
Vdiff = (V1 - V2)
The rejection ratios: if you apply an unwanted signal to either the common mode (at the input) or the power supply (difference between the two power voltages), that unwanted variation will induce an error voltage at the input, equivalent to an offset voltage.
The rejection ratio is the ratio between the (large) unwanted signal and the (small) offset voltage.
Note that the offset voltage here is an equivalent voltage at the input that would give you the measured output voltage.