| Electronics > Beginners |
| DAC circuit |
| << < (3/6) > >> |
| nForce:
Sorry, but I still don't understand. What do you mean by D? DAC? And what is delta? So DAC outputs a voltage between 0 and 3.3 V. And because it's 12-bit DAC the resolution is 3.3/4095? What about those op amps? And there is +10 V or -10 V, shouldn't be the range then 20 V? |
| Wimberleytech:
--- Quote from: nForce on January 26, 2019, 12:08:35 pm ---Sorry, but I still don't understand. What do you mean by D? DAC? And what is delta? --- End quote --- D is the digital input. It has a value between 0 and 4095. When D=0, the output of the DAC is 0, when D=4095, the output of the DAC is 3.3. "delta" is a change. 0 to 3.3V is a delta of 3.3V. 1V to 2V is a delta of 1V. --- Quote ---So DAC outputs a voltage between 0 and 3.3 V. And because it's 12-bit DAC the resolution is 3.3/4095? --- End quote --- The size of an LSB is 3.3/4095. The smallest unit it can resolve is 1 LSB. --- Quote ---What about those op amps? And there is +10 V or -10 V, shouldn't be the range then 20 V? --- End quote --- The opamps do what opamps do. Yes, -10V to +10V is a delta of 20V |
| Wimberleytech:
Here is the circuit with some example values. Use your circuit analysis skills and analyze the signal path. |
| nForce:
So V1 = 1.65 V. And your U1 op amp has a gain of 3. In my case since the resistors are all the same, it has a gain of 2. So: 1.65 * 2 = 3.3, and because the delta is 3.3 then 3.3/3.3 = 1 which is A = 1. Right? But why is delta important here? Thank you for your effort. |
| Wimberleytech:
Delta is important because that is what the original "K" equation was calculating. Calculating small signal gain. Dont worry about the -1.65 V voltage source when calculating K. |
| Navigation |
| Message Index |
| Next page |
| Previous page |