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| nForce:
Thanks. So the second term is 10/1.65, because on the output we have 10 V, and at the input, it's 1.65 V. So the gain is 10/1.65, but why 10, because delta is 20V? And why at the motor it's 1500/10, here we are mixing rpm and voltage. |
| Wimberleytech:
--- Quote from: nForce on January 26, 2019, 04:05:27 pm ---Thanks. So the second term is 10/1.65, because on the output we have 10 V, and at the input, it's 1.65 V. So the gain is 10/1.65, --- End quote --- --- Quote ---but why 10, because delta is 20V? And why at the motor it's 1500/10, here we are mixing rpm and voltage. --- End quote --- The motor speed is 150 rpm/volt. 10 volts yields 1500 rpm. Ergo..."10V" |
| nForce:
Yes, but delta, as you said why is important: Delta at the motor, is 3000 rpm. Not only 1500 rpm. |
| Wimberleytech:
"K" is the gain of the system: K = Speed/D. D is the digital input to the DAC. K is important because this is likely part of a control system where the motor speed is sensed and fed back to the input of the DAC to maintain desired speed. So, it is a control system (I assume). In a control system, K is an important parameter associated with, among other things, stability. If what I just told you makes no sense, then there is no value in me explaining "delta." |
| nForce:
Yes, I understand you. I am just using the knowledge from known values: First-term the numerator has delta which is 3.3 V so the same reason for the motor the numerator would have 3000 which is delta. Delta is the difference between min and max. |
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