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DAC circuit

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nForce:
Thanks. So the second term is 10/1.65, because on the output we have 10 V, and at the input, it's 1.65 V. So the gain is 10/1.65, but why 10, because delta is 20V? And why at the motor it's 1500/10, here we are mixing rpm and voltage.

Wimberleytech:

--- Quote from: nForce on January 26, 2019, 04:05:27 pm ---Thanks. So the second term is 10/1.65, because on the output we have 10 V, and at the input, it's 1.65 V. So the gain is 10/1.65,

--- End quote ---

--- Quote ---but why 10, because delta is 20V? And why at the motor it's 1500/10, here we are mixing rpm and voltage.

--- End quote ---

The motor speed is 150 rpm/volt.  10 volts yields 1500 rpm.  Ergo..."10V"

nForce:
Yes, but delta, as you said why is important: Delta at the motor, is 3000 rpm. Not only 1500 rpm.

Wimberleytech:
"K" is the gain of the system: K = Speed/D.  D is the digital input to the DAC.
K is important because this is likely part of a control system where the motor speed is sensed and fed back to the input of the DAC to maintain desired speed.
So, it is a control system (I assume).  In a control system, K is an important parameter associated with, among other things, stability.
If what I just told you makes no sense, then there is no value in me explaining "delta."

nForce:
Yes, I understand you.

I am just using the knowledge from known values:
First-term the numerator has delta which is 3.3 V so the same reason for the motor the numerator would have 3000 which is delta. Delta is the difference between min and max.

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