0 Members and 1 Guest are viewing this topic.
Calculation looks OK. Unit is RPM/bit.
How do we get "K" in this circuit? Is the calculation correct?Is the second term inverted?Thanks.
Can anyone explain to me how do we get "K"?
This is great, but can you explain/comment in words what are we doing here? Some description.
Sorry, but I still don't understand. What do you mean by D? DAC? And what is delta?
So DAC outputs a voltage between 0 and 3.3 V. And because it's 12-bit DAC the resolution is 3.3/4095?
What about those op amps? And there is +10 V or -10 V, shouldn't be the range then 20 V?
Thanks. So the second term is 10/1.65, because on the output we have 10 V, and at the input, it's 1.65 V. So the gain is 10/1.65,
but why 10, because delta is 20V? And why at the motor it's 1500/10, here we are mixing rpm and voltage.
Yes, I understand you.I am just using the knowledge from known values: First-term the numerator has delta which is 3.3 V so the same reason for the motor the numerator would have 3000 which is delta. Delta is the difference between min and max.
OK, now I understand in terms of units.Can you just say why is then 1500 rpm? Or maybe another person can write it.Let's be consistent:The first term: delta = 3.3 V - 0 V = 3.3 VLast term: delta = 1500 rpm - -1500rpm = 3000 rpm.
Why the first term the range 0-3.3 V is not delta? It seems to me that all the data on the schematic is consistent.Omg, this is going to take forever.