| Electronics > Beginners |
| Demodulation of a data |
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| fateme mrbs:
I have created the first signal in my circuit and the second signal that you see in this picture is what I'm trying to get at the output. Can anybody tell me what circuit can demodulate the first signal and get the second one? |
| Benta:
Simple averaging of the signal (=LPF) followed by a clipping amplifier should get you close. Of course, a synchronous demodulation would be better. |
| fateme mrbs:
Thanks for your answer. I already tried low pas filtering. It doesn't give a neat pulse. |
| Benta:
--- Quote from: fateme mrbs on August 20, 2018, 03:35:55 pm ---Thanks for your answer. I already tried low pas filtering. It doesn't give a neat pulse. --- End quote --- That's why you need to amplify afterwards. Otherwise you won't get a square wave. |
| mikerj:
Your post is showing the signal being demodulated before even the first pulse has been received, and returning back to '0' immediately after the last pulse has been received. It should be obvious that this will not be possible in practice, unless you have already built a time machine. There will always be some latency between input and output. If the amplitude and timing of the pulses is well defined as shown i.e. the logic 1 pluses are always significantly higher amplitude than the logic 0 pluses then you may be able to feed the signal into a (very fast) comparator with a suitable threshold set (somewhere between logic o and logic 1 values), and use the output to trigger a (re-triggerable) monostable with a period just slightly longer then the period between your pulses. The downside of this would be noise immunity, and getting the 0/1 duty cycle correct |
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