Author Topic: Differential input in a mux?  (Read 1380 times)

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Offline erikbrennTopic starter

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Differential input in a mux?
« on: August 13, 2019, 08:44:41 pm »
Hi,

I understand a differential input in terms of an amplifier.

But what's the purpose of an differential input in e.g the AD659 multiplexer? Does a channel switch out the difference voltage between the two inputs?
For what?  Signal-noise ratio stuff??



cheers,
Erik

 

Offline RandallMcRee

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Re: Differential input in a mux?
« Reply #1 on: August 13, 2019, 09:08:20 pm »

There is nothing special there, its a convenient matrix to put in front of a differential amplifier.
Study the logic diagram in the datasheet.
The convenience is that a0 and a1 control eight switches. You don't need eight logic lines because only certain patterns make sense in this scenario.

 

Offline erikbrennTopic starter

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Re: Differential input in a mux?
« Reply #2 on: August 13, 2019, 10:17:02 pm »
Quote
There is nothing special there, its a convenient matrix to put in front of a differential amplifier.
I'm afraid that didn't help....
Quote
Study the logic diagram in the datasheet.
I did. There is nothing to it as you say.
Quote
The convenience is that a0 and a1 control eight switches. You don't need eight logic lines because only certain patterns make sense in this scenario.
Well not really, two address lines can only control four switches, logically speaking. That was the reason for my confusion
I'll rephrase :
Will it ever make sens to provide different analog inputs on one channel with two differential inputs?
If yes,  what for?
If no, why does this setup exist, why not just use a single ended analog mux like AD658? (which has 8 channels, but still same pin-count)

cheers
 

Online ledtester

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Re: Differential input in a mux?
« Reply #3 on: August 13, 2019, 11:01:56 pm »
Here's an example application... Suppose you have 4 stereo audio inputs. With a single ADG659 you can select one of those inputs (a left and right channel pair) for processing, output to an amplifier, etc. If you used a AD658 you would need two of those chips - one for each channel (left and right).
« Last Edit: August 13, 2019, 11:05:29 pm by ledtester »
 

Offline RandallMcRee

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Re: Differential input in a mux?
« Reply #4 on: August 14, 2019, 12:41:38 am »
Quote
There is nothing special there, its a convenient matrix to put in front of a differential amplifier.
I'm afraid that didn't help....
Quote
Study the logic diagram in the datasheet.
I did. There is nothing to it as you say.
Quote
The convenience is that a0 and a1 control eight switches. You don't need eight logic lines because only certain patterns make sense in this scenario.
Well not really, two address lines can only control four switches, logically speaking. That was the reason for my confusion
I'll rephrase :
Will it ever make sens to provide different analog inputs on one channel with two differential inputs?
If yes,  what for?
If no, why does this setup exist, why not just use a single ended analog mux like AD658? (which has 8 channels, but still same pin-count)

cheers

So its very hard to talk to someone who seems to be overcomplicating things. Obviously one control line, being an output, can be an input to any number of switches. Any number. So, the reason, here, is because inputs to a differential amplifier or an instrumentation amplifier come in pairs, V+ and V-. It is *not* generally useful to have any V+ paired with any V-. So they want to be in synchrony. That is what that switch does for you. Maybe it is so simple you are having a hard time with it!

When you do need more flexibility you simply *do* use separate multiplexers and then you need a microcontroller or something to make it work.

Consider the audio analogy and realize that you do not want to have a common ground. You will see that whenever one input is switched in that requires exactly something like the ADG659. (Hint: does it make sense to have an audio input where V+ comes from your cartridge and V- comes from your mp3 player?)

Hope this helps.
 


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