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| Digital signal on the +5V line? |
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| Doctorandus_P:
I also thought about increasing the voltage. Simplest way to do that would be to put a capacitor parralell to the power supply, and then lift the GND pin of that capacitor. That would need 2 transistors, and the capacitor & transistors would have to be dimensioned to not be drained too fast. It is more complicated, with no real benefits and that is why I did not mention it. Just shorting the power supply to GND is easier. The pulses can be very short (10us?, could even be shorter) so the capacitor to bridge those periods does not have to be too big. Alternatively, you could put a series resistor before the "GND" switch, which only dips the power supply. A calculation example: Assume your circuit needs 30mA to function (Use a shunt regulated power supply to keep this constant). Assume a 24V power supply, and limit it's current to 50mA. Assume your secondary circuit works still good when it has 10V on it's input. Then use a switch (Transistor or MOSfet) with 10/(.05-.03)= 500ohm in series. It would also be reasonably simple to use a switched current source on the secondary side. |
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