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| Does This Circuit Destroy an Op Amp |
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| GigaJoe:
opamp consumption approx 3-10ma, not 150. This is a voltage follower. An idea, that opamp doesn't consume current from a source (on input), therefore don't change an input voltage ( or let say an input voltage potential), and do output the same as input but capable with much great load. |
| eev_carl:
--- Quote from: GigaJoe on October 02, 2018, 07:38:19 pm ---opamp consumption approx 3-10ma, not 150. --- End quote --- The LT Spice simulation and my (revised) breadboarding has this at 5 mA. The 150 mA figure I'm throwing around is the current protection setting on my power supply, indicating that it's drawing far too much. |
| nrxnrx:
Are you powering the 14558 with +-10V? https://www.njr.com/semicon/PDF/NJM14558_E.pdf says absolute max is +-7.5 . |
| eev_carl:
--- Quote from: nrxnrx on October 02, 2018, 08:15:35 pm ---Are you powering the 14558 with +-10V? --- End quote --- Yep (Quickly puts in a 4558) |
| rstofer:
--- Quote from: eev_carl on October 02, 2018, 08:04:13 pm --- --- Quote from: GigaJoe on October 02, 2018, 07:38:19 pm ---opamp consumption approx 3-10ma, not 150. --- End quote --- The LT Spice simulation and my (revised) breadboarding has this at 5 mA. The 150 mA figure I'm throwing around is the current protection setting on my power supply, indicating that it's drawing far too much. --- End quote --- The problem has no doubt been solved but I would suggest that if you know the circuit only consumes 5 mA that you set your current protection a lot lower. Maybe 20 mA. I like to keep it tight. If there's an "oopsie", I want it caught before things get warm. Sometimes, when there are large capacitors involved, the voltage will ramp up slowly with the low value of current limit. This may, or may not, be a problem. Regardless, the limit will still prevent the magic smoke from leaking out. |
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