I'm designing a 12-hr CMOS clock and using a 7555 timer as a PWM generator (1.4kHz) for brightness control. The PWM output drives 8 loads, four of which are logic compatible 2n7002ps NMOS gates (30pF at 0.6nc) and the other four are CMOS inputs (three 7-segment decoder blanking inputs and one AND gate input). I may have gone overboard with the load resistors at 7.5k each. My reasoning was that the 7555 output source current is limited to 10mA before the output voltage drops significantly. At 8 loads, the total current is limited to 8*(5/7.5k) = 5.3mA. If the gate capacitance was large enough, this would for a very brief insignificant period of time during the transient on the gate, make the 7555 output voltage equal to 2V.
Now I don't think I really need these gate resistors because the capacitance is so small, and I calculated that with 7.5k gate resistors, the gate voltage would reach 5V in 5*RC = 5*7.5k*30pF = 1.125 us, 0.315% of my PWM switching time (0.157% of the period), so 7.5k would suffice. I believe without the resistors, the current should not be a big issue, but I still added them due to multiple loads.
Do I really need gate resistors to limit the current, even for 8 loads (highlighted in red in attached schematic), since the input capacitances are so small? The same applies for the gate resistors coming from the second counter bit 0, AM/PM indicator flip-flop, and second reset indicator from the XOR (all highlighted in green in attached schematic) since they all at <1Hz.