| Electronics > Beginners |
| Dumb question about resistors in series/parallel |
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| IanB:
--- Quote from: Hero999 on May 02, 2018, 12:14:34 pm ---The other methods such as nodal and mesh analysis work too and arguably are easier to apply, once one is familiar with them, but I prefer my method which I find more intuitive. Indeed, I'd have to consult a textbook if I had to perform mesh and nodal analysis, as I've not done them since college. --- End quote --- Another method I'd like to try myself when I have a free moment is to use the Δ-Y formula to convert the Δ arrangement of R1, R3 and R5 into the equivalent Y network, which then makes the whole network much easier to reduce. |
| IanB:
--- Quote from: Brumby on May 02, 2018, 11:26:40 am ---To TheN00b - Don't let that ^ ^ ^ scare you. You will be able to cope with that a bit further down the road. When you get there, it will be another challenge to learn, but it will provide you with the ability to solve seemingly impossible problems. --- End quote --- This. You are seeing things here that are way beyond what you are expected to learn in high-school physics :) |
| Kirr:
--- Quote from: IanB on May 02, 2018, 01:23:02 pm --- --- Quote from: Hero999 on May 02, 2018, 12:14:34 pm ---The other methods such as nodal and mesh analysis work too and arguably are easier to apply, once one is familiar with them, but I prefer my method which I find more intuitive. Indeed, I'd have to consult a textbook if I had to perform mesh and nodal analysis, as I've not done them since college. --- End quote --- Another method I'd like to try myself when I have a free moment is to use the Δ-Y formula to convert the Δ arrangement of R1, R3 and R5 into the equivalent Y network, which then makes the whole network much easier to reduce. --- End quote --- Yes, Δ-Y as well Y-Δ has to be mentioned. So let me just expand a bit on this method, for completeness. Suppose all available serial and parallel arrangements of resistors are already simplified, and the network is still not a single resistor. What to do next? One simple approach is to apply Δ-Y and Y-Δ transforms. Y-Δ is actually a 3-resistor case of a more general star-mesh transform. While Δ-Y is sometimes more convenient, star-mesh transform has some nice properties: 1. It is always applicable. 2. It always removes one node, leaving you with a smaller network. This means the repeated application of star-mesh transform (followed by parallel and serial simplifications when possible) will slowly but surely solve any finite network. This method is quite mechanical - it does not require thinking about equations or Kirchhoff's laws or much of anything else. So this approach is used in my solver (linked in my sig) - this tool can walk you through this method step by step. |
| Kirr:
--- Quote from: IanMacdonald on May 02, 2018, 07:04:58 am ---Interesting point is that some of these resistor networks are solvable, some are not, or are incredibly difficult to solve. For example an extra resistor between the junctions of R2/R3 and R6/R7 turns this into an entirely different proposition. --- End quote --- Decided to try it. Spoiler link - click to check answer or give up. (Since the new resistor is unspecified, I took the liberty to choose a value of 147 Ω). |
| TheN00b:
--- Quote from: BravoV on May 02, 2018, 04:20:53 am --- --- Quote from: TheN00b on May 02, 2018, 04:16:47 am ---I'll do my best to not be scared. Can't guarantee much though. Lol --- End quote --- LOL .. yeah, it will take a while, practice frequently will make it feels natural, trust me. One thing for sure, now you've learned or at least realized on how NOT to draw a schematic that sucks. :P --- End quote --- And if I do encounter one (probably won't) at least I know how.. who knows, it could be extra credit? --- Quote from: Brumby on May 02, 2018, 11:26:40 am ---To TheN00b - Don't let that ^ ^ ^ scare you. You will be able to cope with that a bit further down the road. When you get there, it will be another challenge to learn, but it will provide you with the ability to solve seemingly impossible problems. --- End quote --- Goodness, I hope so! I want to pursue an EE major someday, so it might be best to learn now though. |
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