Hy!
I was checking some tube transmitter schematic and found this simple one:
Now i wonder if my thinking is correct:
U=350V DC
Prms=15W
Ppeak=30W
P=(U^2)/RL*2
RL=(U^2)/P*2
RL=350^2/15W*2
RL=4000 ohms
Now what i dont understand is:
The tank coil and output coil have turns ratio of 3:1, which means impedance ratio of 9:1
And that monopole antenna has impedance of 36 ohms.
Now RL=36*9=324, when the load for 15Wrms should be 4k.
I assume that the extra impedance we get from that variable capacitor at the bottom of antenna.
Am i correct, if not please correct me, so i don't explode everything lol.
Also i am wondering(if my thinking is correct), can i use a dipole (75 ohms) and about 6-7 turns, giving me impedance ratio of 50:1?
Thanks, Simon.
Please don't waste your time with this thing!
Simple self-excited single device transmitters are usually crap, a circuit where the device is a big, clunky device in a "G" series envelope intended as an audio power output tube is crap "in spades"!
The internal connections in the EL34 are long enough to exceed the inductance of L1, so the circuit will be tuned to a lower frequency than the desired 100MHz.
As well, the stray capacitance of the anode circuit will be larger than the value of C2 , again lowering the resonant point of the LC circuit.
(Back in the day, we used a "rule of thumb" for stray capacitance in video amplifiers using 7 pin & 9 pin"miniature" tubes of approx 20pf--this big octal tube will have a higher value than that).
Even if you get the thing to oscillate, it will be horribly unstable, & the deviation you will get from that varicap is unlikely to produce a reasonable output from a domestic FM receiver.
I don't think your simple impedance calculation is correct, but it's too long since I've messed with this stuff.
If you can find a "Radiotron Designers Manual", an RCA, transmitting tube
Manual, an
old ARRL Handbook, or RSGB Manual, you may find a proper mathematical description of a tube in these operating conditions.